Consider applying the simple electronic polarizability and Clasius-Mossotti equations to diamond.Neglecting losses,αω ω ee oZem=−2( 2 2 )and εε ε ω ωrr o e oNZem−=−12 32( 2 2 )Dispersion in diamondFor diamond we can take Z = 4 (valence electrons only as these are the most responsive),N = 1.8 × 1029 atoms m-3, εr(DC) = 5.7. Find ωo and then find the refractive index at λ = 0.5 μm and5 μm.

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